q=%E6%B3%B0%E7%89%B9%E5%8B%92%28Alexander%2BFraser%2BTytler%29&searchType=standard&isFacet=true&view=standard&rows=10&sortWay=score&sortOrder=desc&curlibcode=GDHYDX&searchWay0=marc&logical0=AND
rows=10&curlibcode=GDHYDX&searchWay0=marc&logical0=AND
泰特勒(Alexander+Fraser+Tytler)