q=K.%2B%E9%98%BF%E5%A7%86%E6%96%AF%E7%89%B9%E6%9C%97%28Karen%2BArmstrong%29&searchType=standard&isFacet=true&view=standard&rows=10&sortWay=score&sortOrder=desc&curlibcode=GDHYDX&searchWay0=marc&logical0=AND
rows=10&curlibcode=GDHYDX&searchWay0=marc&logical0=AND
K.+阿姆斯特朗(Karen+Armstrong)