q=%28%E7%BE%8E%29%E9%98%BF%E5%B0%94%E7%99%BB%C2%B7H%C2%B7%E5%93%88%E8%82%AF%28Alden%2BH.Harken%29&searchType=standard&isFacet=true&view=standard&searchWay=author&rows=10&sortWay=score&sortOrder=desc&searchWay0=marc&logical0=AND
rows=10&searchWay0=marc&logical0=AND
(美)阿尔登·H·哈肯(Alden+H.Harken)