q=%E7%BD%97%E5%BC%97%E6%B4%9B%E6%9E%97%C2%B7%E8%BF%AA%E4%BA%9A%E5%BA%93%26%2340Florin%2BDiacu%26%2341&isFacet=true&view=standard&searchWay=author&rows=10&sortWay=score&sortOrder=desc&searchWay0=marc&logical0=AND
rows=10&searchWay0=marc&logical0=AND
罗弗洛林·迪亚库(Florin+Diacu)